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11x+1=-9x^2
We move all terms to the left:
11x+1-(-9x^2)=0
We get rid of parentheses
9x^2+11x+1=0
a = 9; b = 11; c = +1;
Δ = b2-4ac
Δ = 112-4·9·1
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{85}}{2*9}=\frac{-11-\sqrt{85}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{85}}{2*9}=\frac{-11+\sqrt{85}}{18} $
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